ATP · Slam
Alexander Zverev vs Alejandro Davidovich Fokina
Quarterfinal · Roland Garros 2021
At a glance
Alexander Zverev beat Alejandro Davidovich Fokina 6-4 6-1 6-1. Quarterfinal, Roland Garros 2021 (ATP). Head-to-head: Alexander Zverev 4, Alejandro Davidovich Fokina 2, from 6 matches.
Score
| Player | Set 1 | Set 2 | Set 3 |
|---|---|---|---|
| 6 | 6 | 6 | |
| 4 | 1 | 1 |
Alexander Zverev's path
| Round | Opponent | Result | Score |
|---|---|---|---|
| Second round | Won | 7-6(4) 6-3 7-6(1) | |
| Third round | Won | 6-2 7-5 6-2 | |
| Round of 16 | Won | 6-4 6-1 6-1 | |
| Quarterfinal | Won | 6-4 6-1 6-1 | |
| Semifinal | Lost | 6-3 6-3 4-6 4-6 6-3 |
Alejandro Davidovich Fokina's path
| Round | Opponent | Result | Score |
|---|---|---|---|
| First round | Won | 6-4 6-4 6-3 | |
| Second round | Won | 6-4 6-4 5-7 2-6 6-4 | |
| Third round | Won | 7-6(3) 2-6 7-6(6) 0-6 7-5 | |
| Quarterfinal | Lost | 6-4 6-1 6-1 |