ATP · 250
Christopher O'Connell vs Jenson Brooksby
Quarterfinal · San Diego Open 2022
At a glance
Christopher O'Connell beat Jenson Brooksby 6-4 4-6 7-5. Quarterfinal, San Diego Open 2022 (ATP 250). Head-to-head: Christopher O'Connell 1, Jenson Brooksby 1, from 2 matches.
Score
| Player | Set 1 | Set 2 | Set 3 |
|---|---|---|---|
 Christopher O'Connell | 6 | 4 | 7 |
 Jenson Brooksby | 4 | 6 | 5 |
Christopher O'Connell's path
| Round | Opponent | Result | Score |
|---|---|---|---|
| First round | Jason Murray Kubler | Won | 4-6 6-3 0-0 ret. |
| Round of 16 | Jeff Wolf | Won | 6-3 7-5 |
| Quarterfinal | Jenson Brooksby | Won | 6-4 4-6 7-5 |
| Semifinal | Brandon Nakashima | Lost | 6-4 7-6(3) |
Jenson Brooksby's path
| Round | Opponent | Result | Score |
|---|---|---|---|
| Round of 16 | Mackenzie Mcdonald | Won | 6-4 3-6 6-2 |
| Quarterfinal | Christopher O'Connell | Lost | 6-4 4-6 7-5 |