ATP · Slam
Alexander Zverev vs Arthur Fery
Semifinal · Wimbledon 2026
At a glance
Alexander Zverev beat Arthur Fery 7-6(0) 6-2 6-4. Semifinal, Wimbledon 2026 (ATP). Head-to-head: Alexander Zverev 2, Arthur Fery 0, from 2 matches.
Score
| Player | Set 1 | Set 2 | Set 3 |
|---|---|---|---|
| 7 | 6 | 6 | |
| 6(0) | 2 | 4 |
Alexander Zverev's path
| Round | Opponent | Result | Score |
|---|---|---|---|
| First round | Won | 6-4 6-7(8) 7-6(5) 7-6(0) | |
| Second round | Won | 6-1 6-3 7-6(3) | |
| Third round | Won | 6-2 7-6(4) 6-4 | |
| Round of 16 | Won | 6-4 7-5 3-6 7-6(6) | |
| Quarterfinal | Won | 6-4 6-4 6-2 | |
| Semifinal | Won | 7-6(0) 6-2 6-4 | |
| Final | Lost | 6-7(7) 7-6(2) 6-3 6-4 |
Arthur Fery's path
| Round | Opponent | Result | Score |
|---|---|---|---|
| Third round | Won | 2-6 7-5 2-6 7-6(3) 7-6(5) | |
| Quarterfinal | Won | 6-4 7-6(4) 6-0 | |
| Semifinal | Lost | 7-6(0) 6-2 6-4 |